Question 167444
3R/5-4=11 ---> {{{(3R/5)-4=11}}}, like this?
Then,
{{{3R/5=11+4=15}}}, cross multiply
{{{3R=5*15=75}}} ---> {{{cross(3)R/cross(3)=cross(75)25/cross(3)}}}
{{{highlight(R=25)}}}, Answer
Check back,
{{{((3*25)/5)-4=11}}}
{{{(75/5)-4=11}}}
{{{15-4=11}}}
{{{11=11}}} good
Thank you,
Jojo