Question 167430
{{{y-8=(3/4)(x-2)}}} ---> This follows a Line equation in the format Slope-
Intercept form: {{{y=mx+b}}}
We'll see,
{{{y-8=(3/4)(x-2)}}} , distribute
{{{y-8=(3/4)x-(6/4)}}} ---> {{{6/4}}}--> reduced ---> {{{3/2}}}
{{{y=(3/4)x-(3/2)-8}}}
{{{y=(3/4)x-(3-16)/2}}}
{{{y=(3/4)x-(13/2)}}} ---> {{{slope=3/4}}} and y-intercept @ {{{-13/2}}}
We'll check the points where the line passes the x & y coordinates:
f(x)=0:
{{{y=-13/2}}}
f(y)=0:
{{{(3/4)x=13/2}}} ---> {{{cross(3/4)x/cross(3/4)=(13/2)/(3/4)}}}
{{{x=(13/2)(4/3)=52/6}}}
we'll see the graph
{{{drawing(300,300,-5,15,-10,10,grid(1),graph(300,300,-5,15,-10,10,(3/4)x-13/2), circle(52/6,0,.20),circle(0,-13/2,.20))}}} ---> Line passes thru points {{{52/6}}} @ x-axis and {{{-13/2}}} @ y axis.
Thank you,
Jojo