Question 167290
3/x^2-1/x+5

I understand your question as the following subtraction problem:

(3/x^2) MINUS (1/x + 5)

The denominators are different.

We need the LCD, right?

Our LCD is (x^2)TIMES (x + 5) written simply as (x^2)(x+5).

We now apply the rules of subtraction of fractions with unlike denominators.

In the numerator, we get this over the LCD:

[3(x+5) - (x^2)]/(x^2)(x+5)

We can simplify the numerator a bit more by using the distributive rule to remove the parentheses 3(x+5).

This will leave us with:

(3x + 15 - x^2)/(x^2)(x+5)

Did you follow?