Question 23528
Since now you know your new centre which is (2,2) and your a absolute value the equation goes like this: {{{(x-2)^2/9-(y-2)^2/b^2}}} all you have now to do is to find the absolute value for b.


since you know that the transverse axis is 6 ---> 6/2=3^2 = 9 (a value)
The centre is (h-a,k) and (h+a,k) 
(6-2,2) and (6+2,2) -> the distance between these two points is 4 (b value)


Since 3^2 = 9 (b)
 4^2=16 (a) 
Now pulg the terms into the equation. 
Hence, the equation for the hyperbola is {{{(x-2)^2/9 -(y-2)^2/16 = 1}}}