Question 167269
4(x+1)=2(x-3)-(1-2x)

The first thing you want to do is remove the parentheses using the distributive rule.

On the left side we have: 4(x + 1) = 4x + 4.

On the right side we have: 2(x-3)-(1-2x) = 2x - 6 - 1 + 2x.

We now have this equation:

4x + 4 = 2x - 6 - 1 + 2x.

We combine like terms and simplify, (if possible), to find x.

4x - 2x - 2x = -4 - 6 - 1

On the left side we get a zero.

LOOK:

4x - 2x -2x = 4x - 4x = 0.

We can stop right here and conclude that there is no solution for x in this equation as you typed it.

Did you follow?

In your reply, you said:

"um...sorry but it didnt help cause i didnt get it at all shouldn't there be a solution cause i got something different"

========================================

My new reply:

Here is your original equation:

4(x+1)=2(x-3)-(1-2x)

We simplify the equation by first using the distributive rule.

On the left side of the equation we have this:

4(x+1) = 4x + 4

On the right side we have this:

2(x-3)-(1-2x)= 2x - 6 - 1 + 2x

We now have this equation:

4x + 4 = 2x - 6 - 1 + 2x

We now combine like terms:

4x + 4 = 4x - 7

We continue to combine like terms by placing the terms with x together and the numbers without the letter x together.

4x - 4x = -4 - 7

On the left side, a positive 4x and a negative 4x cancel out and thus become zero.

You cannot continue to simplify if your equation is 0 = -11, right?

Here is my conclusion:

1-You either typed the question incorrectly

OR

2-This equation has no solution, which means it is empty set.