Question 2860
Your question will be written as,
{{{ sqrt(5x^2-9) = 2x }}}
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Then taking the square root to the other side we get,
{{{ (5x^2-9) = (2x)^2 }}}
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{{{ (5x^2-9) = (4x^2) }}}
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Taking (4x^2) to the other side we get,
{{{ (5x^2 - 4x^2 - 9) = 0 }}}
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Which then gives us,
{{{ (x^2 -9) = 0 }}}
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Taking 9 to the other side we get,
{{{ (x^2) = 9 }}}
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Taking square root on both sides we get,
{{{ x = sqrt(9) }}}
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Therefore <B> x={3,-3} </b>
<P>
Hope this helped,
Best of luck.