Question 167346
Solve for m:
{{{4m^2-28m+49 = 0}}} Factor the quadratic equation.
{{{(2m-7)(2m-7) = 0}}} Apply the zero product rule:
{{{2m-7 = 0}}} or {{{2m-7 = 0}}}
If {{{2m-7 = 0}}} then {{{2m = 7}}} and so {{{m = 7/2}}}
So the solution is a double root: {{{m = 7/2}}} or {{{m = 3.5}}}
{{{graph(400,400,-3,10,-5,50,4x^2-28x+49)}}}