Question 21774
log (x+1) = log 2


You can do this one, even if you don't know anything about logarithms!  This is what you need:  
{{{log ((THIS)) = log ((THAT)) }}} means {{{THIS = THAT}}}
{{{log ((x+1))= log ((2)) }}} means {{{x+1 = 2}}}


So, x= 1


Wasn't that easy!!??


R^2 at SCC