Question 167201
{{{Log[5](3x-1) - Log[5](2x+7) = 0}}} Add {{{Log[5](2x+7)}}} to both sides.
{{{Log[5](3x-1) = Log[5](2x+7)}}} Now apply the rule: If{{{Log[b](M) = Log[b](N)}}}, then {{{M = N}}}, so...
{{{(3x-1) = (2x+7)}}} Subtract 2x from both sides.
{{{x-1 = 7}}} Add 1 to both sides.
{{{highlight(x = 8)}}}