Question 167122
x varies directly as the square of s and inversely as t. H
x = {{{s^2/t}}}
:
How does x change when s is doubled?
x = {{{(2s)^2/(t)}}} = {{{(4s^2)/(t)}}}; x increase 4 times
:
:
When both s and t are doubled?
x = {{{(2s)^2/(2t)}}} = {{{(4s^2)/(2t)}}} =  {{{(2s^2)/(t)}}}: We can say that x is doubled