Question 167001
Given: {{{4x=4x^2-3}}}
Combine terms: {{{4x^2-4x-3=0}}}, Working Eqn
Divide whole eqn by 4:
{{{cross(4)x^2/cross(4)-cross(4)x/cross(4)-3/4=0/4}}}
{{{x^2-x-3/4=0}}}---->By Pyth. Theorem
where ----{{{system(a=1,b=-1,c=3/4=0.75)}}}
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}} , Plug in the values
ANSWER: {{{3/2}}} & {{{-1/2}}}
Check, go back working eqn, (use -1/2)
{{{4(-1/2)^2-4(-1/2)-3=0}}}
{{{cross(4)(1/cross(4))-cross(4)(2)(-1/cross(2))-3=0}}}
{{{1-(-2)-3=0}}}
{{{1+2-3=0}}}
{{{3-3=0}}}
Thank you,
Jojo