Question 166991
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Use the "point-slope" form of a linear equation:
y-y1 = m(x-x1)
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For your problem:
(x,y)=(2,3)
(x1,y1)=(5,y)
m = 3/4
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Plug it in and solve for y:
y-y1 = m(x-x1)
3-y = (3/4)(2-5)
3-y = (3/4)(-3)
12-4y = (3)(-3)
12-4y = -9
12 = 4y-9
21 = 4y
21/4 = y
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