Question 166950
2x^2-3x+1=0
2x^2-3x = -1
2(x^2 - (3/2)x) = -1
2(x^2 - (3/2)x + 9/16) = -1 + 9/8
2(x-(3/4))^2 = -8/8 + 9/8
2(x-(3/4))^2 = 1/8
(x-(3/4))^2 = 1/16
x-(3/4) = (+-)1/4
x = (3/4)(+-)1/4
.
x = {2/4, 4/4}
x = {1/2, 1}