Question 166855
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As it looks, "+2" is part of "t" as it inversely proportional to "B". Then it follows this eqn: {{{B[1](t[1]+2)=B[2](t[2]+2)}}}
where --- {{{B[1]=12}}},{{{t[1]=1}}},{{{B[2]=unknown}}},{{{t[2]=4}}}
Continuing our eqn,
{{{12*(1+2)=B[2](4+2)}}}
{{{12*3=6B[2]}}}
{{{36=6B[2]}}} ------> {{{cross(36)6/cross(6)=cross(6)B[2]/cross(6)}}}
{{{highlight(B[2]=6)}}}, Answer
*That is true, when {{{t[1]=1}}} goes up {{{t[2]=4}}}, then {{{B[1]=12}}} goes down {{{B[2]=6}}} ---> inversely proportional.
Thank you,
Jojo</pre>