Question 23511
{{{1/(x+1) = x-4}}}
{{{1 = (x-4)(x+1)}}}
{{{1 = x^2 - 3x - 4}}}
{{{x^2 - 3x - 5 = 0}}}

This does not factorise easily, so use the quadratic formula. you will have been shown how to do this, since this question uses it.


Answer is {{{x = (3 +- sqrt(29))/2}}}


Work out the positive version, {{{x = (3 + sqrt(29))/2}}}, and then write the integer below and above this number, for example if the number was 4.86123, then write 4 and 5.


jon