Question 166847
Let {{{x=number}}}
Via condition:
1st contn: neg. nine increased by three ---> {{{-9+3}}}
2nd condtn: multiplied by a number ----> {{{(-9+3)x}}}
3rd condtn: equals neg. six --------> {{{(-9+3)x=-6}}}
Continuing 3rd condtn,
{{{-6x=-6}}} ----> {{{cross(-6)x/cross(-6)=cross(-6)/cross(-6)}}}
{{{highlight(x=1)}}},the Number
 Check Via 3rd condtn:
{{{(-9+3)1=-6}}}
{{{(-6)1=-6}}}
{{{-6=-6}}}
Thank you,
Jojo