<PRE><B>Question 166851</B>
The path of a diver is y=-4/9x^2+24/9x+12. Where y is the height (in feet) and x is the horizontal distance (in feet) from the end of the diving board. What is the maximum height of the dive? Verify your answer using a graphing utility.
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You have a quadratic with a = (4/9), b = (24/9), c = 12
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max occurs when x = -b/2a = -(24/9)/[2(4/9)] = -3
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Height when x = -3 is (-4/9)(-3)^2 + (24/9)(-3) + 12
= -4 - 8 + 12
=  0 ft.
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Comment: That is not a very realistic answer; check your problem statement.
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Cheers,
Stan H.</PRE>