Question 166812
how do you factor say {{{x^2+5x+15=12}}}
All you have to do is subtract 12 from each side and you get {{{x^2+5x+3=0}}}
Now you can use the quadratic equation to solve.
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
such that {{{ax^2+bx+c=0}}}
Remember that this formula is = to 0 instead of 1.