Question 166760
{{{log(x+8)+ log(x-1)=1}}}
{{{log((x+8)(x-1))=1}}}
{{{(x+8)(x-1)= 10^1}}}
{{{x^2 + 7x -8 = 10}}}
{{{x^2 +7x - 18=0}}}
{{{(x+9)(x-2) = 0}}}
x=-9 or x=2

Sub back into the original equation to find the value(s) that work
Log of a negative number is not defined, so only x=2 works