Question 166680
# 1





{{{x+3y=13}}} Start with the given equation.



{{{3y=13-x}}} Subtract {{{x}}} from both sides.



{{{3y=-x+13}}} Rearrange the terms.



{{{y=(-x+13)/(3)}}} Divide both sides by {{{3}}} to isolate y.



{{{y=((-1)/(3))x+(13)/(3)}}} Break up the fraction.



{{{y=-(1/3)x+13/3}}} Reduce.



So the equation {{{y=-(1/3)x+13/3}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-1/3}}} and the y-intercept is {{{b=13/3}}} note: the y-intercept is the point *[Tex \LARGE \left(0,\frac{13}{3}\right)]



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Answer:



So the slope is {{{m=-1/3}}}




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# 2



{{{2x-y=-9}}} Start with the given equation.



{{{-y=-9-2x}}} Subtract {{{2x}}} from both sides.



{{{-y=-2x-9}}} Rearrange the terms.



{{{y=(-2x-9)/(-1)}}} Divide both sides by {{{-1}}} to isolate y.



{{{y=((-2)/(-1))x+(-9)/(-1)}}} Break up the fraction.



{{{y=2x+9}}} Reduce.



So the equation {{{y=2x+9}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=2}}} and the y-intercept is {{{b=9}}} note: the y-intercept is the point *[Tex \LARGE \left(0,9\right)]




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Answer:



So the slope is {{{m=2}}}