Question 166604
Write the equation of a quadratic that has zeros of 5 and 1 with F(0)=1. I understand you need to multiply (x-5)(x-1) to get the polynomial, but f(0) wouldnt equal 1.
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Right.  That is why you need a variable factor,like "k" below.
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f(x) = k(x-5)(x-1)
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Now you get f(0) = k(-5)(-1) = 1
5k = 1
k = 1/5
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EQUATION:
y = (1/5)(x-5)(x-1)
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Cheers,
Stan H.