Question 166425
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so lets call d1=r1*T1  1st cyclist  T1=T+3 r1=6
.............d2=r2*T2  2nd cyclist  T2=T   r2=10
:
d1 has to equal d2 since they travel the same distance.
:
equations:
{{{d1=6(T+3)}}}
{{{d1=10T}}}
and since: {{{d1=d2}}}

then:{{{6T+18=10T}}}----->{{{4T=18}}}    {{{T=4.5}}}
:
2nd cyclist was cycling {{{T=4.5hours}}} before he caught the 1st cyclist.