Question 166514
First, get rid of parens
{{{x^2a-x^2b+a^2b-a^2x+b^2x-b^2a}}} rearrange and regroup
{{{(a-b)x^2-(a^2-b^2)x+(a^2b-b^2a)}}} expand {{{(a^2-b^2)}}} 
{{{(a-b)x^2-(a-b)(a+b)x+ab(a-b)}}} factor out {{{(a-b)}}}
{{{(a-b)(x^2-(a-b)x+ab)}}}=
Since {{{x^2-(a-b)x+ab}}} equals {{{(x-a)(x-b)}}}, we have

{{{(a-b)(x-a)(x-b)}}}


Hope this helps---ptaylor