Question 166437
{{{Ax^3-Bx^2-Cx-D=0}}}

so B=A-3
   C=3B--->3(A-3) or 3A-9
   D=A+2
A+B+C+D=-4

so substituting into the last equation{{{ A+(A-3)+(3A-9)+(A+2)=-4}}}

simplify{{{6A-10=-4}}}---->{{{6A=6}}}  {{{A=1}}}

{{{A=1}}}
{{{B=1-3=-2}}}
{{{C=3(-2)=-6}}}
{{{D=1+2=3}}}