Question 166429
distance going     call d1
distance returning call d2
d1=d2
time returning call t
time going     call t-6.3
rate going is 32mph
rate returning is 10mph

d1=32(6.3-t)
d2=10t

32(6.3-t)=10t
201.6-32t=10t
42t=201.6
t=4.8
so {{{d=10(4.8)=48miles}}}