Question 166273
1) {{{-x-3y=-4}}} ------------> LINE EQN 1
it follows: {{{y=mx+b}}},
{{{-3y=x-4}}}
{{{y=(-1/3)x+(4/3)}}} ----> {{{slope=-1/3}}}; y-intercept={{{4/3}}}
f(y)=0:
{{{x=(-4/3)(-3/1)=12/3=4}}}
f(x)=0:
{{{y=4/3}}}
2) {{{3x+y=16}}} ---------------> LINE EQN 2
{{{y=-3x+16}}} ---> {{{slope=-3}}}; y-intercept ={{{16}}}
f(y)=0:
{{{3x=16}}} ----> {{{x=16/3}}}
f(x)=0:
{{{y=16}}}
See graph:
{{{drawing(300,300,-7,7,-7,18,grid(1),graph(300,300,-7,7,-7,18,(-1/3)(x)+4/3,-3x+16),circle(4,0,.2),circle(0,4/3,.2),circle(16/3,0,.20),circle(0,16,.20))}}} ----> Green Line {{{3x+y=16}}} @ points (16/3,16); Red Line {{{-x-3y=-4}}} @ points (4,4/3)
Thank you,
Jojo