Question 23477
First of all congratulations on writing the equation box for this particular problem!!  

{{{2x^3y^5/5(x^4y^2)^3)}}} 


Next, remove parentheses in the denominator.  Remember that when you raise a power to a power you multiply exponents!!


{{{2x^3y^5/5(x^12y^6)}}} 


Next, you can divide out the {{{x^3}}} in the numerator with {{{x^12}}} in the denominator, leaving {{{x^9}}} in the denominator (subtract exponents!!).  You can divide out the {{{y^5}}} in the numerator with the {{{y^6}}} in the denominator, leaving a {{{y^1}}} in the denominator.  The 2 stays in the numerator, and the 5 stays in the denominator.


The final result is:  {{{2/5(x^9y)}}}


R^2 at SCC