Question 166337
I am assuming that (2) is actually an exponent?
2zx(2)y=18 where x=1,z=y
so we rewrite the equation with the information given, we use 1 in place of our x and y in place of z;
{{{2y(1)^2y=18}}}
{{{2y^2=18}}}
divide each side by 2;
{{{y^2 = 9}}}
take the square root of each side;
{{{sqrt(y^2)=sqrt(18)}}}
we end with;
y=9
Hope this is clear and I helped.
:)