Question 166393
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system of equations {{{y=x^4-3x³}}}---> EQN 1, and {{{y=2x-6}}}----> EQN 2:
EQN 1:
If you look on the graph below, we find {{{highlight(x=1.25)}}} closest,so
{{{y=(1.25)^4-3(1.25)^3=2.44-5.859}}}
{{{highlight(y=-3.418)}}}
EQN 2:
f(y)=0: {{{2x=6}}} --->{{{cross(2)x/cross(2)=cross(6)3/cross(2)}}}
{{{x=3}}}
f(x)=0: {{{y=-6}}}
SEE GRAPH:
{{{drawing(300,300,-7,7,-9,10,grid(1),graph(300,300,-7,7,-9,10,x^4-3x^3,2x-6),circle(3,0,.20),circle(1.25,-3.418,.20))}}} --- See points of intersection-->(3,0) & (1.25,-3.418)
Thank you,
Jojo</pre>