Question 166338
{{{2zx^2y=18}}} Start with the given equation



{{{2y(1)^2(y)=18}}} Plug in x=1 and z=y



{{{2y*(y)=18}}} Square 1 to get 1 and multiply



{{{2y^2=18}}} Multiply



{{{y^2=9}}} Divide both sides by 2



{{{y=3}}} or {{{y=-3}}} Take the square root of both sides (don't forget the negative answer)



So when  x=1 and z=y, then {{{y=3}}} or {{{y=-3}}}