Question 166309
Find the expected value of the random variable in the experiment.
Three cards are drawn from a deck without replacement. THe number of aces is counted.
The choices are a) .2308 b) 1 c).2174 d)1.0134
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The results are 0,1,2, or 3 aces
P(0 aces) = 48C3/52C3
P(1 ace) =  3[4/52][48/51][47/50]
P(2 aces) = 3[4/52][3/51][48/50]
P(3 aces) = 3[4/52][3/51][2/50][48/49]
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To get the expected value, multiply each "result" value by its probability
and then add the 4 results. 
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Cheers,
Stan H.