Question 166305


{{{(x+6)^2=121}}} Start with the given equation.



{{{x+6=0+-sqrt(121)}}} Take the square root of both sides.



{{{x+6=sqrt(121)}}} or {{{x+6=-sqrt(121)}}} Break up the "plus/minus" to form two equations.



{{{x+6=11}}} or {{{x+6=-11}}}  Take the square root of {{{121}}} to get {{{11}}}.



{{{x=-6+11}}} or {{{x=-6-11}}} Subtract {{{6}}} from both sides.



{{{x=5}}} or {{{x=-17}}} Combine like terms.



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Answer:



So the solutions are {{{x=5}}} or {{{x=-17}}}.