Question 166117
{{{abs(3x-1)/(x^2+4)<0}}}
The denominator is always positive. 
The numerator is always positive or zero. 
Therefore, there is no value of x such that the left hand side would be less than zero. 
No solution.
{{{abs(3x-1)/(x^2+4)<0}}}
{{{abs(3x-1)<0}}}
By definition, 
{{{abs(Y)>=0}}} for all Y.
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Graphical verification. 
{{{ graph( 300, 300, -10, 10, -1, 1, (abs(3x-1))/(x^2+4)) }}}