Question 165963
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Remember: {{{FastCar=FC}}}; {{{SlowCar=SC}}}
In the condition: FC exceeded SC by 6mph ---> {{{FC=SC+6mph}}}, EQN 1
We know that {{{Speed=Distance/Time}}} and {{{Speed=SC+FC}}} that covered 287 miles in 3.5 hours (10:30-7:00=3.5 hrs) right?
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Putting into eqn all given via our formula:
{{{SC+FC=287/3.5}}}, plug in EQN 1:
{{{SC+SC+6=287/3.5}}}
{{{(2SC+6)3.5=287}}}, cross multiply
{{{7SC+21=287}}} ----> {{{7SC=287-21=266}}}
{{{cross(7)SC/cross(7)=cross(266)38/cross(7)}}}
{{{highlight(SC=38mph)}}}, Speed of Slow Car
Via EQN 1,
{{{highlight(FC=38+6=44mph)}}}, Speed of Fast Car
In doubt? Both cars should travlled a Distance of 287 miles in 3.5 hrs. Let's see,
{{{(SC+FC)(3.5)=287mi}}}
{{{(38+44)(3.5)=287}}}
{{{81*3.5=287}}}
{{{287mi=287mi}}}
Thank you,
Jojo</pre>