Question 166189
Perimeter is the length 'around' the rectangular area. {{{P = 2L + 2W}}}
Area is the area of the enclosed rectangle {{{A = L * W}}}

{{{27 = 2L + 2W}}}
{{{27-2W = 2L }}}
{{{(27-2W)/2 = L }}}

{{{A = L * W}}}
{{{35 = ((27-2W)/2)  * W }}}
{{{35 = (27W - 2W^2)/2 }}}
{{{70 = 27W - 2W^2}}}
{{{2W^2 - 27W + 70 = 0}}}
Now use the quadratic equation to solve
*[invoke quadratic "x", 2, -27, 70]