Question 166130
Method #1 (somewhat of a long way):


{{{(-3x^4y^2)^3=(-3x^4y^2)(-3x^4y^2)(-3x^4y^2)=(-3)(-3)(-3)(x^4)(x^4)(x^4)(y^2)(y^2)(y^2)=-27x^(4+4+4)y^(2+2+2)=-27x^12y^6}}}



Method #2 (much faster way):


{{{(-3x^4y^2)^3=((-3)^1x^4y^2)^3=(-3)^(1*3)x^(4*3)y^(2*3)=(-3)^3x^12y^6=-27x^12y^6}}}