Question 166126
{{{5x^2-125=0}}} Start with the given equation



{{{5(x^2-25)=0}}} Factor out the GCF 5


{{{5(x+5)(x-5)=0}}} Factor {{{x^2-25}}} to get {{{(x+5)(x-5)}}} (note: use the difference of squares.)




Now set each factor equal to zero:

{{{x+5=0}}} or  {{{x-5=0}}} 


{{{x=-5}}} or  {{{x=5}}}    Now solve for x in each case



So our answers are 


 {{{x=-5}}} or  {{{x=5}}}