<PRE><B>Question 166112</B>
THE TIME REQUIRED TO EMPTY A TANK VARIES INVERSELY AS THE RATE OF PUMPING. IF A PUMP CAN EMPTY A TANK IN 45 MINUTES AT THE RATE OF 600 GALLONS PER MINUTE, HOW LONG WILL IT TAKE THE PUMP TO EMPTY THE SAME TANK AT THE RATE OF 1000 GALLONS PER MINUTE?

Let t = equal the time required to empty a tank

Let r = rate of pumping

Let k = the constant of variation

t varies inversely as r, is written:

t = k/r

600 = k/45

600 (45) = k

27,000 = k

Find t when r = 1000

t = 27,000/1000

t = 27 minutes





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