Question 165949
{{{log4(x+3)+log4(x-3)=2}}}
then
{{{log4((x+3)(x-3))=2}}}
then
{{{(x+3)(x-3)=4^2}}}
then
{{{x^2-9=16}}}
then
{{{x^2=25}}}
then
{{{x=5}}}or {{{x=-5}}}
but if x=-5 then log4(x+3) not exists
so solution is

{{{x=5}}}