Question 165909
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{{{radius=4.2m}}}
{{{V=(4/3)(pi)r^3}}} --------------> working eqn
{{{V=(4/3)(pi)4.2^3}}}
{{{highlight(V=98.784(pi)m^3)}}}, Answer
.
{{{(diameter)=12ft}}} --->{{{radius=dia/2=12/2=6ft}}}
{{{V=(4/3)(pi)(6^3)}}}
{{{V=288(pi)ft^3}}} ----> {{{V=(288(pi)cross(ft^3))(1m^3/35.29cross(ft^3))}}}
{{{highlight(V=25.63m^3)}}}, Answer
Thank you,
Jojo</pre>