Question 165868
Let the number be -n (a negative real number), then, from the problem description, you have:
{{{(-n+16)^2 = 36}}} "...the square of the sum of the number and 16 is equal to 36." 
Square the left side of the equation.
{{{n^2-32n+256 = 36}}} Subtract 36 from both sides.
{{{n^2-32n+220 = 0}}} Solve by factoring this quadratic equation.
{{{(n-10)(n-22) = 0}}} So...
{{{n = 10}}} or {{{n = 22}}}
The answers should be: -10 and -22