Question 165745
lets call the smaller a and the larger b

b=2a-5  a+b=28  solve for a in the 2nd equation and we get a=28-b.  now take the value of a and substitute it into the 1st equation.                         b=2(28-b)-5  now distribute the right side
b=56-2b-5 combine terms
b=51-2b  add 2b to each side
3b=51 divide by 3
b=17   and since a=28-b(17) then a =11

so the smaller number is 11 and the larger is 17