<PRE><B>Question 165650</B>
A merchant wishes to mix two grades of coffee, one of which sells for $0.80 per pound and one of which sells for $1.20 per pound. He wants to sell the mixture $1.10 per pound. If he has 25 pounds of the $0.80 coffee, how much of the $1.20 per pound coffee must he add so that the value of the final mixture is equal to the total value of the other two?
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80 cent coffee DATA:
Amt. = 25 lbs. ; value = 80*25 = 2000 cents
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120 cent coffee DATA:
Amt = x lbs. ; value = 120x cents
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110 cent coffee DATA:
Amt = 25+x lbs value = 110(25+x)
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EQUATION:
value + value = value
2000 + 120x = 110(25+x)
2000 + 120x = 2750 + 110x
10x = 750
x = 75 lbs (amount of $1.20 coffee needed for the mixture)
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Cheers,
Stan H.</PRE>