Question 23433
Going data:
distance =?; rate=12mph; time=t
Comming back data:
distance =?; rate=36mph; time=1-t
Formula: d=rt
EQUATION:
 Going distance = Coming distance
     12t = 36(1-t)
     12t = 36-36t
     48t= 36
        t = 3/4 hr. (Going time)
Therefore distance =(3/4)(12)= 9 miles