Question 165612
{{{P(x)=x^3-3x^2+25x-75}}}={{{x^2*(x-3)+25*(x-3)}}}={{{(x^2+25)*(x-3)=0}}}
then


{{{x^2+25=0}}} or {{{x-3=0}}}
then

x^2=-25 then x=5i or -5i
x-3=0 then x=3

Answer:
zeros are: 5i,-5i,3