Question 165538
Here's an example.
{{{x^2+3x+2=0}}}
You can factor the quadratic equation.
{{{(x+2)(x+1)=0}}}
Zero product rule says either the first factor or the second factor could equal zero so solve for both.
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First factor:
{{{x+2=0}}}
{{{x=-2}}}
Second factor:
{{{x+1=0}}}
{{{x=-1}}}
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The solution set (zeros) for the equation are x=-1,-2.
You can check the answers by plugging into the equation or you could graph the equation to verify.
{{{x^2+3x+2=0}}}
{{{(-2)^2+3(-2)+2=0}}}
{{{4-6+2=0}}}
{{{0=0}}}
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{{{ graph( 300, 300, -3, 1, -3,1,  x^2+3x+2) }}}