Question 23426
Let one of the numbers be "x".
Then, the 2nd number is 25-x.
EQUATION:
The sum of the squares of the numbers is 313
   x^2 + (25-x)^2= 313
   x^2 + 625 -50x+x^2 = 313
  2x^2-50x+312=0
*[invoke quadratic "x", 2,-50,312]
x=1      (1st number)
25-x=13  (2nd number)

Cheers,
Stan H.