Question 165468
so dividing x-2 into {{{x^4-5x^2+3x-1}}} and the first term will be {{{x^3)}}} which multiplied by x-2 = {{{x^4-2x^3}}} subt this from the original and you left with {{{-2x^3-5x^2+3x-1}}} so our next term will be {{{-x^2}}} when multiplied by x-2 equals {{{-2x^3+2x^2}}} now you subtract this from our last remaining terms and get {{{-7x^2+3x-1}}}. our next term will be {{{-7x}}} which when multiplied by x-2 gives us{{{-7x^2+14x-1}}} which when subt from our last remaining terms gives us {{{11x-1}}}. our next term will be 11 when multiplied by x-2 gives us {{{11x-22)}}} which when subt from our last remaining term gives us 21 so if we take all our terms we have {{{x^3-x^2-7x+11}}} with a remainder
of {{{21/(x-2)}}}