<PRE><B>Question 165302</B>
There were 10 more reds than 8 times the number of blues.
R = 8*B + 10 (first equation)
Also, the number of reds was 5 less tahn 11 times the number of blues.
R = 11*B - 5 (second equation)
since they both = R, then they are equal to each other.
8*B + 10 = 11*B - 5
subtract 8*B from both sides.
10 = 3*B - 5
add 5 to both sides.
15 = 3*B
divide both sides by 3.
5 = B
substitute for B in first equation.
R = 8*5 + 10
R = 40 + 10
R = 50
substitute for R and B in second equation.
50 = 11*5 - 5
50 = 55 - 5
50 = 50
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R = 50
B = 5
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