Question 21436
(20+sqrt5-x) = (sqrtx+10)...I ASSUME THE PROBLEM IS 
20  +(5-X)^0.5=(X+10)^0.5...IF THIS IS SO IT HAS NO SOLUTION AND DONT BREAK YOUR HEAD ON THAT.BECAUSE X CANNOT BE MORE THAN FIVE OR LESS THAN -10,AS  THEN WE GET IMAGINARY NUMBERS AND IN THAT RANGE OF X BETWEEN -10 AND +5 THERE IS NO SOLUTION WHICH SATISFIES THAT EQN.AT X=5 WE GET LHS =20..AND RHS CANNOT BECOME 20..AT X=-10 RHS IS ZERO AND LHS CANNOT BE ZERO

IF NOT PLEASE WRITE THE PROBLEM CORRECTLY BY PUTTING APPROPRIATE BRACKETS...FOR.EX.WHETHER  YOU MEAN
(sqrtx+10)=10+SQRT(X)...OR...SQRT(X+10)..SIMILARLY

(20+sqrt5-x)=20-5+SQRT(X)...OR....20+SQRT(X-5)
THEN I SHALL WORK OUT THE PROBLEM